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Firefox DevToiols block all requests

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Hi!

When you open network tab on Firefox devtools there is request blocking option. The hint below text box says "Add URL patterns here to block matching requests" but there is no documentation how to write patterns. I tried to google it like 10 different ways and did not find any documentation.

Hi! When you open network tab on Firefox devtools there is request blocking option. The hint below text box says "Add URL patterns here to block matching requests" but there is no documentation how to write patterns. I tried to google it like 10 different ways and did not find any documentation.

所有回覆 (5)

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This is merely about the URL you want to block. This can be the full URL to only block one specific file or only block files on a specific path or block everything from a server. You can possibly drag a specific request to the "block resource when the URL contains" bar and then remove trailing text until you are satisfied.

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You didnt read my question. I asked about patterns. For example how do I block every request that goes to let's say any subdomain of google.com (but not google.com itself)?

Or other example, how do I block any request? For example I dont know in advance what url/uri will be posted when I click submit button. I want to click button anyways to see request it makes but I dont want server to get that request.

So the question is how do I write patterns? Does it use regex? Does it have some custom syntax?

Any example patterns?

由 fdoywugozklvsndgax 於 修改

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I don't think that there is any pattern supported like you mean.

You can check the action on the form in the inspector to see what request will be send and block that URL.

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I cant accept it as answer. The text in devtools says "Start by adding a pattern or dragging a row from the network table"

It has word pattern.

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I cant accept it as answer. The text in devtools says "Start by adding a pattern or dragging a row from the network table"

It has word pattern.

Also the simplest pattern that blocks everything is *. This already proves that there is at least 1 pattern.