Avatar for Username

Αναζήτηση στην υποστήριξη

Προσοχή στις απάτες! Δεν θα σας ζητήσουμε ποτέ να καλέσετε ή να στείλετε μήνυμα σε κάποιον αριθμό τηλεφώνου ή να μοιραστείτε προσωπικά δεδομένα. Αναφέρετε τυχόν ύποπτη δραστηριότητα μέσω της επιλογής «Αναφορά κατάχρησης».

Μάθετε περισσότερα

Αυτό το νήμα αρχειοθετήθηκε. Παρακαλούμε κάντε νέα ερώτηση αν χρειάζεστε βοήθεια.

Can you log into bugzilla.mozilla.org with your Firefox account?

  • 2 απαντήσεις
  • 1 έχει αυτό το πρόβλημα
  • 2 προβολές
  • Τελευταία απάντηση από FredMcD

TechHorse
TechHorse
more options

Or will you need a separate Bugzilla account?

What is throwing me is that when I visit https://bugzilla.mozilla.org I am prompted for my Primary PW, and FF autofills the login form with my old FF support account credentials, indicating that the old support account and the bugzilla page are recognised by FF as being linked?

So before I try logging into https://bugzilla.mozilla.org with either the auto-filled old FF support credentials, or my newer FF Account credentials, does this page come under your FF Account umbrella? Thanks.

Or will you need a separate Bugzilla account? What is throwing me is that when I visit https://bugzilla.mozilla.org I am prompted for my Primary PW, and FF autofills the login form with my old FF support account credentials, indicating that the old support account and the bugzilla page are recognised by FF as being linked? So before I try logging into https://bugzilla.mozilla.org with either the auto-filled old FF support credentials, or my newer FF Account credentials, does this page come under your FF Account umbrella? Thanks.

Όλες οι απαντήσεις (2)

TechHorse
TechHorse Ιδιοκτήτης ερώτησης
more options

In case anyone else ever has this query, it seems that no, Mozilla's Bugzilla site is a distinct entity that needs its own separate account. It is not covered by your Firefox account.

FredMcD
FredMcD
more options

Mozilla is divided into several separate support/service areas. Each uses their own username and password logins.